System Design

check it here: 

060419_1430_poster_multistack_electrolysis.pdf

Mechanical Design

Check the Electrolyser Mechanical Design Page for more info:

Mechanical Design

Hydrogen Storage: 

check the full presentation: 050419_ElectrolysisOfWater.pptx

PCS Design

Check the Electrolyser Process Control System Design Page for more info:

PCS Design

Needed inormations for the design and the calculations :

The proposed spaces were 10.65, 9.20, 8.25, 7.25, 6.30, 6.05, 4.35, 4.15, and 3.40 millimetres. From the nine different analysed distances between electrodes, it can be said that the best performance was reached by one of the smallest distances proposed, 4.15 mm. When the same distance between electrodes was compared (the same and different distance between electrodes and separator), the one that had almost twice the distance (negative compartment) presented an increase in current density of approximately 33% with respect to that where both distances (from electrodes to separator) are the same. That indicates that the stichometry of the electrolysis reaction influenced the performance. [1]

[2]

L = A x R/ρ.

R = L x ρ / A = L / (A x K )

K =1/ρ  .

U= R×I

current density i nalkaline electrolysis= 0,2-0,4 A/cm square

calculating the current and the voltage for the existing cells 

the bigger cell in which the distance between the eectrodes is 3,6 cm

cell details :

The radius of the surface which touches the solution : 14,6 cm .

The distance between the electrode and the membrane : 3,6 cm .

We filled only 2/3 of the cell volume .

Temperature = 25 degree celsius 

So R =  (3,6 cm)/((446,21 cm square × 0,125 ))  = 0,0645 Ω .

I = 178,484 Amperes

U = 11,52 Volt

the smaller cells in which the distance between the eectrodes is 1,8 cm

L = 1,8 cm

Inner Radius = 14,6 cm

So  R =(1,8 cm)/((446,21 cm square × 0,125 ))  = 0,0322 Ω

I = 178,484 Amperes

U =5,747 volt

calculating the current the voltage and the distance between electrodes of the multistage electrolyser cell :

L= A x  ( 6)/(A )  x 0,3375 = 2,025 cm

I = 0,4 x the surface that touches the solution=0,4 x A=0,4×3,14×r×r

U = 2,4 Volt

So the distance betwee the two electrodes shall be 2,025 cm .

And from the text above we seen that it is better to divide this distance into 3 parts

2 parts on the hydrogen production site and one on the oxygene production .

That means 0,675 cm from the anode to the membrane and 1,35 cm from the caathode to the membrane .

References :

[1] :  Straight-Parallel Electrodes and Variable Gap for Hydrogen and Oxygen Evolution Reactions

[2] : https://backend.orbit.dtu.dk/ws/portalfiles/portal/6368532/Electrical+conductivity+measurements.pdf

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